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Calculate the binding energy per nucleon of calcium nucleus $(_{20}{Ca}^{40})$. Given, Mass of $_{20}{Ca}^{40} = 39.962589\;u$; Mass of neutron $m_n = 1.008665\;u$; Mass of proton $m_p = 1.007825\;u$; $1\;u = 931\;MeV$.
Calculate the binding energy per nucleon of calcium nucleus $(_{20}{Ca}^{40})$. Given, Mass of $_{20}{Ca}^{40} = 39.962589\;u$; Mass of neutron $m_n = 1.008665\;u$; Mass of proton $m_p = 1.007825\;u$; $1\;u = 931\;MeV$.
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The isotopes $Ra-226$ undergoes $\alpha$ decay with a half-life of $1620$ years. What is the activity of $1\;g$ of $Ra-226$? Avogadro number = $6.023 * 10^{23}\; /mole$.
The isotopes $Ra-226$ undergoes $\alpha$ decay with a half-life of $1620$ years. What is the activity of $1\;g$ of $Ra-226$? Avogadro number = $6.023 * 10^{23}\; /mole$.
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Find the half-life of $U^{238}$, if one gram of it emits $1.24 * 10^4$ $\alpha - particles$ per second. (Avogadro's Number = $6.023 * 10^{23}$).
Find the half-life of $U^{238}$, if one gram of it emits $1.24 * 10^4$ $\alpha - particles$ per second. (Avogadro's Number = $6.023 * 10^{23}$).
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The energy liberated in the fission of a single uranium-235 atom is $3.2 * 10^{-11}\;J$. Calculate the power production corresponding to the fission of $1\;gm$ of uranium per day. Assume Avogadro constant as $6 * 10^{23}\;mol^{-1}$.
The energy liberated in the fission of a single uranium-235 atom is $3.2 * 10^{-11}\;J$. Calculate the power production corresponding to the fission of $1\;gm$ of uranium per day. Assume Avogadro constant as $6 * 10^{23}\;mol^{-1}$.
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A city requires $10^7 watts$ of electrical power on the average. If this is to be supplied by a nuclear reactor of efficiency $20\; \%$. Using $_{92}{U}^{235}$ as the fuel source, calculate the amount of fuel required per day (Energy released per fission $_{92}{U}^{235} = 200\;MeV$).
A city requires $10^7 watts$ of electrical power on the average. If this is to be supplied by a nuclear reactor of efficiency $20\; \%$. Using $_{92}{U}^{235}$ as the fuel source, calculate the amount of fuel required per day (Energy released per fission $_{92}{U}^{235} = 200\;MeV$).
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