Calculate the binding energy per nucleon of calcium nucleus $(_{20}{Ca}^{40})$. Given, Mass of $_{20}{Ca}^{40} = 39.962589\;u$; Mass of neutron $m_n = 1.008665\;u$; Mass of proton $m_p = 1.007825\;u$; $1\;u = 931\;MeV$.
Calculate the binding energy per nucleon of calcium nucleus $(_{20}{Ca}^{40})$. Given, Mass of $_{20}{Ca}^{40} = 39.962589\;u$; Mass of neutron $m_n = 1.008665\;u$; Mass of proton $m_p = 1.007825\;u$; $1\;u = 931\;MeV$.